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Proof step 15 from proof congmod-inverse-pos (previous step)

i0 < 0, 0 < j, 1 < j, 0 ≤ j, ≡mod(i0, 1, j) ⊦ ∃ i. ≡mod(i, 1, j) ∧ 0 ≤ i

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: 1

Additional information

Used simplifier rules: cong-same: ⊦ ≡mod(i, i, j); Used terms: 1