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Proof step 29 from proof congmod-inverse-pos (previous step)

0 < j, (i * i1) |%| j = 1, gcd(i, j) = 1, i0 < 0, ≡mod(i * i0, 1, j), 0 ≤ j, 0 ≤ i, 0 < i1, 0 < j, 0 ≤ i1 ⊦ (i * i1) |%| j = 1 |%| j, ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
(i * i1) |%| j = 1, gcd(i, j) = 1, i0 < 0, ≡mod(i * i0, 1, j), 0 ≤ j, 0 ≤ i, 0 < i1, 0 < j, 0 ≤ i1 ⊦ 1 = 1 |%| j, ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0

Proof step 29 from proof congmod-inverse-pos (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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