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Proof step 5 from proof congmod-inverse-pos (previous step)

gcd(i, j) = 1, 0 ≤ i, 0 ≤ j, ≡mod(i * i0, 1, j) ⊦ ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0

User applied rule exists right

And obtained the following new goals

Proof step 6:
gcd(i, j) = 1, 0 ≤ i, 0 ≤ j, ≡mod(i * i0, 1, j) ⊦ ≡mod(i * i0, 1, j) ∧ 0 ≤ i0, ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0

Rule argument

pos: right 1 terms: i0 abort: F discard: F computed: T

Additional information

Used terms: i0