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Proof step 7 from proof congmod-inverse-smallest (previous step)

gcd(i, j) = 1, ≡mod(i * i0, 1, j), 0 ≤ i0, 0 ≤ i, 0 < j, j ≤ i0, 0 < i0 ⊦ j = 0, ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0 ∧ i0 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information