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Proof step 1 from proof diff-primes-neg (conclusion)

⊦ prime(j) ∧ j ≠ 2 → ¬ dups(countFun(0, (j - 1) / 2, λ i. (~1 - i ^2) |%| j))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information