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Proof step 53 from proof diff-primes (previous step)

0 ≤ j, m < i→n(1 + (j - 1) / 2), n < i→n(1 + (j - 1) / 2), prime(j), n→i(m) ≤ (j - 1) / 2, n→i(n) ≤ (j - 1) / 2, j | n→i(m) ^2 - n→i(n) ^2, 0 < j ⊦ countFun(0, (j - 1) / 2, λ i. i ^2 |%| j) = [], j = 2, m = n, ~1 = (j - 1) / 2, n→i(m) ^2 = (n→i(m) - n→i(n)) * (n→i(m) + n→i(n)) + n→i(n) ^2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 54:
⊦ i ^2 = i * i
Proof step 55:
0 ≤ j, m < i→n(1 + (j - 1) / 2), n < i→n(1 + (j - 1) / 2), prime(j), n→i(m) ≤ (j - 1) / 2, n→i(n) ≤ (j - 1) / 2, j | n→i(m) * n→i(m) - n→i(n) ^2, 0 < j ⊦ countFun(0, (j - 1) / 2, λ i. i ^2 |%| j) = [], j = 2, m = n, ~1 = (j - 1) / 2, n→i(m) * n→i(m) = (n→i(m) - n→i(n)) * (n→i(m) + n→i(n)) + n→i(n) ^2

Rule argument

spec: int-square inst: name: Square-def seq: ⊦ i ^2 = i * i subst: [i] → [n→i(m)] flags: rewrite

Additional information

Used terms: n→i(m)