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Proof step 19 from proof even-sum (previous step)

even(i1) ∧ even(i2) ∨ odd(i1) ∧ odd(i2), even(i) ∧ even(i0) ∨ odd(i) ∧ odd(i0) ⊦ ∃ i3, i4, i5, i6. even(i3 + i4) ∧ even(i5 + i6) ∧ i3 ^2 + i4 ^2 + i5 ^2 + i6 ^2 = (i ^2 + i0 ^2) + i1 ^2 + i2 ^2

User applied rule exists right

And obtained the following new goals

Proof step 20:
even(i1) ∧ even(i2) ∨ odd(i1) ∧ odd(i2), even(i) ∧ even(i0) ∨ odd(i) ∧ odd(i0) ⊦ even(i + i0) ∧ even(i1 + i2) ∧ i ^2 + i0 ^2 + i1 ^2 + i2 ^2 = (i ^2 + i0 ^2) + i1 ^2 + i2 ^2

Rule argument

pos: right 1 terms: i, i0, i1, i2 abort: F discard: T computed: T

Additional information

Used terms: i, i0, i1, i2