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Proof step 27 from proof even-sum (previous step)

odd(i1) ∧ even(i2) ∨ even(i1) ∧ odd(i2), odd(i) ∧ even(i0) ∨ even(i) ∧ odd(i0) ⊦ ∃ i3, i4, i5, i6. even(i3 + i4) ∧ even(i5 + i6) ∧ i3 ^2 + i4 ^2 + i5 ^2 + i6 ^2 = (i ^2 + i0 ^2) + i1 ^2 + i2 ^2

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

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