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Proof step 2 from proof ex-modeq-half (previous step)

odd(j), 0 < j ⊦ ∃ i. ≡mod(i, i0, j) ∧ abs(i) ≤ j / 2

User applied rule exists right

And obtained the following new goals

Proof step 3:
odd(j), 0 < j ⊦ ≡mod(i0 |%| j, i0, j) ∧ abs(i0 |%| j) ≤ j / 2, ∃ i. ≡mod(i, i0, j) ∧ abs(i) ≤ j / 2

Rule argument

pos: right 1 terms: i0 |%| j abort: F discard: F computed: F

Additional information

Used terms: i0 |%| j