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Proof step 4 from proof fermat-2 (previous step)

gcd(i, j) = 1 → (∃ i0. ≡mod(i * i0, 1, j)), gcd(j, i) = 1, prime(j) ⊦ ≡mod(i ^ (j - 1), 1, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
gcd(j, i) = 1, prime(j), ≡mod(i * i0, 1, j) ⊦ ≡mod(i ^ (j - 1), 1, j)

Rule argument

Additional information

Used simplifier rules: gcd-com: ⊦ gcd(i, j) = gcd(j, i); from specification int-gcd