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Proof step 19 from proof four-square-congmod (previous step)

i2 ^2 + i1 ^2 + i0 ^2 + i ^2 = j0 * j, 1 < j, 0 < j, 0 < j0, j0 | abs(i3 - i2), ≡mod(i4, i1, j0), 0 < i3 ^2 + i4 ^2 + (j0 * i7 + i0)^2 + (j0 * i5 + i)^2 ⊦ j0 = 1, j = 2, j0 | i3 ^2 + i4 ^2 + (j0 * i7 + i0)^2 + (j0 * i5 + i)^2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
i2 ^2 + i1 ^2 + i0 ^2 + i ^2 = j0 * j, ≡mod(i4, i1, j0), 0 < i3 ^2 + i4 ^2 + (j0 * i7 + i0)^2 + (j0 * i5 + i)^2, 1 < j, 0 < j, 0 < j0, j0 | i3 - i2 ⊦ j0 = 1, j = 2, j0 | i3 ^2 + i4 ^2 + (j0 * i7 + i0)^2 + (j0 * i5 + i)^2

Rule argument

Additional information

Used simplifier rules: div-abs-02: ⊦ i | abs(j) ↔ i | j; from specification int-gcd