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Proof step 31 from proof four-square-divides-all (previous step)

j0 * i7 = (j0 * i5 + i2)^2 + (j0 * i6 + i1)^2 + (j0 * i8 + i0)^2 + (j0 * i3 + i)^2, i2 ^2 + i1 ^2 + i0 ^2 + i ^2 = j0 * j, i7 < j0, j0 < j, j0 * i7 < j0 ^2, 0 < j, i7 < j, 1 < j0, 0 < j0 ^2, 1 < j0 ^2, 0 < j0, 0 < i7, 1 < j ⊦ j = 2, j0 = 1, j0 | ((i2 * (j0 * i5 + i2) + i1 * (j0 * i6 + i1)) + i0 * (j0 * i8 + i0)) + i * (j0 * i3 + i) ∧ j0 | i * (j0 * i8 + i0) + i2 * (j0 * i6 + i1) - i1 * (j0 * i5 + i2) + i0 * (j0 * i3 + i)

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: i * (j0 * i8 + i0) + i2 * (j0 * i6 + i1) - i1 * (j0 * i5 + i2) + i0 * (j0 * i3 + i) = j0 * (i * i8 + i2 * i6 - i1 * i5 + i0 * i3)

Additional information

Used formulas: i * (j0 * i8 + i0) + i2 * (j0 * i6 + i1) - i1 * (j0 * i5 + i2) + i0 * (j0 * i3 + i) = j0 * (i * i8 + i2 * i6 - i1 * i5 + i0 * i3)