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Proof step 26 from proof four-square-mod-zero (previous step)

(j0 * i0)^2 + (j0 * i2)^2 + (j0 * i)^2 + (j0 * i3)^2 = j0 * j, prime(j), j0 < j, 1 < j, 0 < j, 0 < j0, 0 ≤ j ⊦ j0 = 1, j = 2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
⊦ i ^2 = i * i
Proof step 28:
(j0 * i0) * j0 * i0 + (j0 * i2)^2 + (j0 * i)^2 + (j0 * i3)^2 = j0 * j, prime(j), j0 < j, 1 < j, 0 < j, 0 < j0, 0 ≤ j ⊦ j0 = 1, j = 2

Rule argument

spec: int-square inst: name: Square-def seq: ⊦ i ^2 = i * i subst: [i] → [j0 * i0] flags: rewrite

Additional information

Used terms: j0 * i0