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Proof step 1 from proof four-square-odd-ls (conclusion)

odd(j0), abs(i3) ≤ j0 / 2, abs(i4) ≤ j0 / 2, abs(i5) ≤ j0 / 2, abs(i6) ≤ j0 / 2, 0 < j0, j0 ≠ 1, 0 < i3 ^2 + i4 ^2 + i5 ^2 + i6 ^2 ⊦ i3 ^2 + i4 ^2 + i5 ^2 + i6 ^2 < j0 ^2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
odd(j0), abs(i3) ≤ j0 / 2, abs(i4) ≤ j0 / 2, abs(i5) ≤ j0 / 2, abs(i6) ≤ j0 / 2, j0 ^2 ≤ i3 ^2 + i4 ^2 + i5 ^2 + i6 ^2, 0 < j0, 0 < i3 ^2 + i4 ^2 + i5 ^2 + i6 ^2 ⊦ j0 = 1

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs