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Proof step 27 from proof lagrange-lemma (previous step)

0 ≤ j0, j1 ≤ (j - 1) / 2, j0 ≤ (j - 1) / 2, prime(j), 0 ≤ j, 0 ≤ j1, j | ~1 - j1 ^2 + j0 ^2, 0 < j ⊦ j = 2, ∃ i, i0, j0. 1 + i ^2 + i0 ^2 = j0 * j ∧ 0 < j0 ∧ j0 < j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 28:
⊦ j | i - i0 ↔ j | i0 - i
Proof step 29:
0 ≤ j0, j1 ≤ (j - 1) / 2, j0 ≤ (j - 1) / 2, prime(j), 0 ≤ j, 0 ≤ j1, j | j1 ^2 + j0 ^2 - ~1, 0 < j ⊦ j = 2, ∃ i, i0, j0. 1 + i ^2 + i0 ^2 = j0 * j ∧ 0 < j0 ∧ j0 < j

Rule argument

spec: int-gcd inst: name: divides-minus seq: ⊦ j | i - i0 ↔ j | i0 - i subst: [i0, i, j] → [j1 ^2 + j0 ^2, ~1, j] flags: rewrite

Additional information

Used terms: j1 ^2 + j0 ^2, ~1, j