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Proof step 3 from proof lagrange-lemma (previous step)

⊦ prime(j) ∧ j ≠ 2 → dups(countFun(0, (j - 1) / 2, λ i. i ^2 |%| j) + countFun(0, (j - 1) / 2, λ i. (~1 - i ^2) |%| j))

Lemma diff-primes-dups