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Proof step 33 from proof lagrange-lemma (previous step)

j * i = (j1 ^2 + j0 ^2) + 1, 0 ≤ j1, 0 ≤ j, prime(j), j0 ≤ (j - 1) / 2, j1 ≤ (j - 1) / 2, 0 ≤ j0, 0 < j ⊦ j = 2, ∃ i, i0, j0. 1 + i ^2 + i0 ^2 = j0 * j ∧ 0 < j0 ∧ j0 < j

User applied rule exists right

And obtained the following new goals

Proof step 34:
j * i = (j1 ^2 + j0 ^2) + 1, 0 ≤ j1, 0 ≤ j, prime(j), j0 ≤ (j - 1) / 2, j1 ≤ (j - 1) / 2, 0 ≤ j0, 0 < j ⊦ j = 2, 1 + j1 ^2 + j0 ^2 = i * j ∧ 0 < i ∧ i < j

Rule argument

pos: right 2 terms: j1, j0, i abort: F discard: T computed: F

Additional information

Used terms: j1, j0, i