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Proof step 35 from proof lagrange-lemma (previous step)

j * i = (j1 ^2 + j0 ^2) + 1, 0 ≤ j1, 0 ≤ j, prime(j), j0 ≤ (j - 1) / 2, j1 ≤ (j - 1) / 2, 0 ≤ j0, 0 < j ⊦ j = 2, 0 < i ∧ i < j

User applied rule cut formula

And obtained the following new goals

Proof step 36:
0 < i, j * i = (j1 ^2 + j0 ^2) + 1, 0 ≤ j1, 0 ≤ j, prime(j), j0 ≤ (j - 1) / 2, j1 ≤ (j - 1) / 2, 0 ≤ j0, 0 < j ⊦ j = 2, 0 < i ∧ i < j
Proof step 69:
j * i = (j1 ^2 + j0 ^2) + 1, 0 ≤ j1, 0 ≤ j, prime(j), j0 ≤ (j - 1) / 2, j1 ≤ (j - 1) / 2, 0 ≤ j0, 0 < j ⊦ 0 < i, j = 2, 0 < i ∧ i < j

Rule argument

fma: 0 < i

Additional information

Used formulas: 0 < i