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Proof step 1 from proof mod-abs-neg (conclusion)

⊦ i < 0 ∧ 0 < j → i |%| abs(j) = i |%| j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: abs-16: ⊦ 0 < j → abs(j) = j; from specification int-abs