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Proof step 4 from proof mod-abs-pos (previous step)

¬ ¬ j < 0, 0 ≤ i ⊦ i |%| abs(j) = i |%| j, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
j < 0, 0 ≤ i ⊦ i |%| ~ j = i |%| j, j = 0

Rule argument

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%abs-08: ⊦ i < 0 → abs(i) = ~ i; from specification int-abs