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Proof step 13 from proof mod-ex-div (previous step)

0 < j + j1, j1 < 0, i0 * j + j1 < 0, i0 < j + j1, i0 < j, i0 ≤ 0, 0 < j, 0 ≤ j ⊦ ∃ j0. i0 * j = j * j0 + j

User applied rule exists right

And obtained the following new goals

Proof step 14:
0 < j + j1, j1 < 0, i0 * j + j1 < 0, i0 < j + j1, i0 < j, i0 ≤ 0, 0 < j, 0 ≤ j ⊦ i0 * j = j * (i0 - 1) + j

Rule argument

pos: right 1 terms: i0 - 1 abort: F discard: T computed: F

Additional information

Used terms: i0 - 1