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Proof step 2 from proof mod-ex-div (previous step)

⊦ j = 0, ∃ j0. i = j * j0 + i |%| j

User applied rule exists right

And obtained the following new goals

Proof step 3:
⊦ j = 0, i = j * i / j + i |%| j, ∃ j0. i = j * j0 + i |%| j

Rule argument

pos: right 2 terms: i / j abort: F discard: F computed: F

Additional information

Used terms: i / j