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Proof step 14 from proof mod-mult-add (previous step)

0 < j ∧ i0 ≤ 0 ∧ i0 < j, ∀ i1, j, i. i→n(i1) < i→n(i0) → 0 < j ∧ i1 ≤ 0 ∧ i1 < j → (i + i1 * j) |%| j = i |%| j ⊦ (i + i0 * j) |%| j = i |%| j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information