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Proof step 2 from proof mod-mult-add (previous step)

0 < j ⊦ (i + i0 * j) |%| j = i |%| j

User applied rule cut formula

And obtained the following new goals

Proof step 3:
0 < i0, 0 < j ⊦ (i + i0 * j) |%| j = i |%| j
Proof step 12:
0 < j ⊦ 0 < i0, (i + i0 * j) |%| j = i |%| j

Rule argument

fma: 0 < i0

Additional information

Used formulas: 0 < i0