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Proof step 20 from proof mod-pot-pot (previous step)

0 < j, 0 < j, 0 ≤ i2, 0 < j, 0 ≤ i2, ∀ i1, j, i. i→n(i1) < i→n(i2 + 1) → 0 ≤ i1 ∧ 0 < j → (i |%| j) ^ i1 |%| j = i ^ i1 |%| j ⊦ ((i |%| j) ^ i2 |%| j * (i |%| j) |%| j) |%| j = ((i ^ i2 |%| j) |%| j * (i |%| j) |%| j) |%| j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
0 < j, 0 ≤ i2, ∀ i1, j, i. i→n(i1) < i→n(i2 + 1) → 0 ≤ i1 ∧ 0 < j → (i |%| j) ^ i1 |%| j = i ^ i1 |%| j ⊦ ((i |%| j) ^ i2 |%| j * i |%| j) |%| j = (i ^ i2 |%| j * i |%| j) |%| j

Rule argument

Additional information

Used simplifier rules: mod-mod: ⊦ 0 < j → (i |%| j) |%| j = i |%| j;