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Proof step 11 from proof mod-rec-any (previous step)

0 < j, i < j, 0 ≤ i ⊦ i = (i - j) |%| j

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-mod inst: name: mod-zero-neg seq: ⊦ i < 0 ∧ abs(i) < j ∧ 0 < j → i |%| j = i + j subst: [j, i] → [j, i - j] flags: rewrite, current

Additional information

Used simplifier rules: Sub-def: ⊦ i + (j - i) = j; from specification int-abs%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used terms: j, i - j