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Proof step 30 from proof bits2bits-def (
previous step
)
¬ bits.first ∧ bits ≠ [] ⊦ bits = [], int2bits(bits2uint(bits.rest)) = sgn(bits)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 31
:
⊦ bits = [], int2bits(bits2uint(bits.rest)) = sgn(bits), bits.first
Rule argument
Additional information