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Proof step 33 from proof bits2bits-def (previous step)

⊦ int2bits(bits2uint(bits0)) = sgn(false ' + bits0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 34:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 35:
¬ 0 ≤ bits2uint(bits0) ⊦ int2bits(bits2uint(bits0)) = sgn(false ' + bits0)
Proof step 36:
0 ≤ bits2uint(bits0) ⊦ uint2bits(bits2uint(bits0)) = sgn(false ' + bits0)

Rule argument

name: int2bits-pos rotate: F subst: [i] → [bits2uint(bits0)]

Additional information

Used terms: bits2uint(bits0)