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Proof step 4 from proof bits2bits-def (
previous step
)
¬(¬ bits.first ∧ bits ≠ []) ⊦ bits = [], int2bits(bits2int(bits)) = sgn(bits)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
bits.first ⊦ bits = [], int2bits(bits2int(bits)) = sgn(bits)
Rule argument
Additional information