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Proof step 1 from proof bits2bits-invert (conclusion)

⊦ bits ≠ [] → bits2int(bitsinvert(int2bits(bits2int(bits)))) = bits2int(bitsinvert(bits))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ bits = [], bits2int(bitsinvert(sgn(bits))) = bits2int(bitsinvert(bits))

Rule argument

Additional information

Used simplifier rules: bits2bits-def: bits ≠ [] ⊦ int2bits(bits2int(bits)) = sgn(bits);