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Proof step 2 from proof bits2int-fill (previous step)

⊦ bits = [], bits2int(fillsgn(n, bits)) = bits2int(bits)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ bits2int(sgn(bits)) = bits2int(bits)
Proof step 4:
⊦ bits = [], bits2int(sgn(fillsgn(n, bits))) = bits2int(bits)

Rule argument

name: bits2int-sgn rotate: T subst: [bits] → [fillsgn(n, bits)]

Additional information

Used terms: fillsgn(n, bits)