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Proof step 2 from proof bits2int-inj (previous step)

⊦ bits = [], bits0 = [], bits2int(bits) = bits2int(bits0) ↔ sgn(bits) = sgn(bits0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ int2bits(i) = int2bits(j) ↔ i = j

Rule argument

name: int2bits-inj rotate: T subst: [j, i] → [bits2int(bits0), bits2int(bits)]

Additional information

Used simplifier rules: bits2bits-def: bits ≠ [] ⊦ int2bits(bits2int(bits)) = sgn(bits); Used terms: bits2int(bits0), bits2int(bits)