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Proof step 6 from proof bits2int-inv (previous step)

bits = boolvar + bits0, boolvar ⊦ bits = [], ~1 = bits2int(bits) + bits2int(bitsinvert(bits))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⊦ bits2uint((false ' + bitsinvert(bits0))+1) = bits2uint(bitsinvert(bits0)) + 1

Rule argument

Additional information

Used simplifier rules: bits2int-pos: ⊦ bits2int(false ' + bits) = bits2uint(bits);%bits2int-neg: ⊦ bits2int(true ' + bits) = ~ bits2uint(bitsinvert(true + bits) +1);% ⊦ i + ~1 = i - 1;% ⊦ i - j = i0 ↔ i = i0 + j;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + ~ j = i - j;% ⊦ bitsinvert(true ' + bits) = false + bitsinvert(bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;