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Proof step 13 from proof bits2int-lasteq (previous step)

⊦ bits0 = [], bits2uint((false ' + bitsinvert(bits1))+1) * 2 + bits2int(bits0 + false ') = 0 ↔ bits2uint((false ' + bitsinvert(bits1))+1) + bits2int(bits0) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits)
Proof step 15:
¬(¬ (bits0 + false ').first ∧ bits0 + false ' ≠ []) ⊦ bits0 = [], bits2uint((false ' + bitsinvert(bits1))+1) * 2 + bits2int(bits0 + false ') = 0 ↔ bits2uint((false ' + bitsinvert(bits1))+1) + bits2int(bits0) = 0
Proof step 17:
¬ (bits0 + false ').first ∧ bits0 + false ' ≠ [] ⊦ bits0 = [], bits2uint((false ' + bitsinvert(bits1))+1) * 2 + bits2uint(bits0 + false ') = 0 ↔ bits2uint((false ' + bitsinvert(bits1))+1) + bits2int(bits0) = 0

Rule argument

name: bits2int-pos-02 rotate: F subst: [bits] → [bits0 + false ']

Additional information

Used terms: bits0 + false '