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Proof step 2 from proof bits2int-lasteq (previous step)

⊦ bits = [], bits0 = [], bits2int(bits + boolvar ') = bits2int(bits0 + boolvar ') ↔ bits2int(bits) = bits2int(bits0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ boolvar ∧ ¬ bits.first ∧ bits ≠ [] → bits2int(bits + boolvar ') = bits2int(bits) * 2 + 1
Proof step 4:
¬(boolvar ∧ ¬ bits.first ∧ bits ≠ []) ⊦ bits = [], bits0 = [], bits2int(bits + boolvar ') = bits2int(bits0 + boolvar ') ↔ bits2int(bits) = bits2int(bits0)
Proof step 39:
boolvar ∧ ¬ bits.first ∧ bits ≠ [] ⊦ bits = [], bits0 = [], bits2int(bits) * 2 + 1 = bits2int(bits0 + boolvar ') ↔ bits2int(bits) = bits2int(bits0)

Rule argument

name: bits2int-rec rotate: F subst: [boolvar, bits] → [boolvar, bits]

Additional information

Used terms: boolvar, bits