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Proof step 41 from proof bits2int-lasteq (previous step)

bits = boolvar + bits1 ⊦ bits0 = [], bits2int(bits) * 2 + 1 = bits2int(bits0 + true ') ↔ bits2int(bits) = bits2int(bits0), bits = [], boolvar

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 42:
⊦ bits0 = [], 1 + 2 * bits2uint(bits1) = bits2int(bits0 + true ') ↔ bits2uint(bits1) = bits2int(bits0)

Rule argument

Additional information

Used simplifier rules: bits2int-pos: ⊦ bits2int(false ' + bits) = bits2uint(bits);% ⊦ boolvar ' + bits ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar + bits = boolvar ' + bits;