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Proof step 44 from proof bits2int-lasteq (previous step)

¬(true ∧ ¬ bits0.first ∧ bits0 ≠ []) ⊦ bits0 = [], 1 + 2 * bits2uint(bits1) = bits2int(bits0 + true ') ↔ bits2uint(bits1) = bits2int(bits0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information