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Proof step 1 from proof bits2int-neg-1bit (conclusion)

⊦ i < 0 → bits2int(true ' + int2bits(i)) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ bits2int(bits) = bits2int(sgn(bits))
Proof step 3:
⊦ i < 0 → bits2int(sgn(true ' + int2bits(i))) = i

Rule argument

name: bits2int-sgn-intro rotate: F subst: [bits] → [true ' + int2bits(i)]

Additional information

Used terms: true ' + int2bits(i)