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Proof step 10 from proof bits2int-nls (previous step)

0 ≤ ~ bits2int(bits), bits2int(bits) < 0, 2 ^ n→i(# bits) + bits2int(bits) < 0, 2 + # bits ≤ # uint2bits(~ bits2int(bits)) ⊦ bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
bits2int(bits) < 0, 2 ^ n→i(# bits) + bits2int(bits) < 0, 2 + # bits ≤ # uint2bits(~ bits2int(bits)), bits2int(bits) ≤ 0 ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + 0 = i;% ⊦ i ≤ ~ j ↔ i + j ≤ 0;