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Proof step 17 from proof bits2int-nls (previous step)

¬(¬ bitsinvert(bits) +1.first ∧ bitsinvert(bits) +1 ≠ []), bits.first, 0 < bits2uint(bitsinvert(bits) +1), 2 ^ n→i(# bits) < bits2uint(bitsinvert(bits) +1), 2 + # bits ≤ # uint2bits(bits2uint(bitsinvert(bits) +1)), 0 ≤ bits2uint(bitsinvert(bits) +1) ⊦ bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
bits.first, 0 < bits2uint(bitsinvert(bits) +1), 2 ^ n→i(# bits) < bits2uint(bitsinvert(bits) +1), 2 + # bits ≤ # uint2bits(bits2uint(bitsinvert(bits) +1)), 0 ≤ bits2uint(bitsinvert(bits) +1), bitsinvert(bits) +1.first ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ bits +1 ≠ [] ↔ false;