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Proof step 7 from proof bits2int-nls (previous step)

bits2int(bits) < 0, 2 ^ n→i(# bits) + bits2int(bits) < 0, ¬ 0 - bits2int(bits) ≤ 2 ^ n→i(# bits) → 2 + # bits ≤ # int2bits(~ bits2int(bits)) ⊦ bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
bits2int(bits) < 0, 2 ^ n→i(# bits) + bits2int(bits) < 0, 2 + # bits ≤ # int2bits(~ bits2int(bits)) ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ i + j = j + i;% ⊦ ~ i ≤ j ↔ 0 ≤ i + j;% ⊦ 0 - i = ~ i;