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Proof step 1 from proof bits2int-ones-01 (conclusion)

⊦ ¬ false ∈ bits → bits2int(bits + true ' + bits0) = bits2int(true ' + bits0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
bits ≠ [], ¬ (¬ bits.first) ∈ bits0 ⊦ bits2int(bits0 + bits) = bits2int(bits)

Rule argument

name: bits2int-sign rotate: F subst: [bits, bits0] → [true ' + bits0, bits]

Additional information

Used simplifier rules: bits2int-neg: ⊦ bits2int(true ' + bits) = ~ bits2uint(bitsinvert(true + bits) +1);% ⊦ boolvar + bits = boolvar ' + bits;% ⊦ bitsinvert(true ' + bits) = false + bitsinvert(bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ ~ i = j ↔ i + j = 0;% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ boolvar ' ≠ [];% ⊦ (boolvar ' + bits).first ↔ boolvar; Used terms: true ' + bits0, bits