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Proof step 15 from proof bits2int-ones-02 (previous step)

bits.first ⊦ bits + bits0 = [], bits = [], 2 ^ n→i(# bits0) = bits2uint(bitsinvert(bits).butlast + true ' + bits0), false ∈ bits, true ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ ¬ true ∈ bits → bits2uint(bits + bits0) = bits2uint(bits0)

Rule argument

name: bits2uint-zeros-02 rotate: F subst: [bits0, bits] → [true ' + bits0, bitsinvert(bits).butlast]

Additional information

Used simplifier rules: bits2uint-2pot: ⊦ ¬ true ∈ bits → bits2uint(true ' + bits) = 2 ^ n→i(# bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bitsinvert(bits) = [] ↔ bits = [];%bits ≠ [] ⊦ boolvar ∈ bits.butlast → boolvar ∈ bits; (forward)% ⊦ true ∈ bitsinvert(bits) ↔ false ∈ bits; Used terms: true ' + bits0, bitsinvert(bits).butlast