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Proof step 18 from proof bits2int-ones-02 (previous step)

bits.first, true ∈ bits0 ⊦ bits + bits0 = [], bits = [], bits2uint(bitsinvert(bits0) +1) = bits2uint(bitsinvert(bits) + bitsinvert(bits0) +1), false ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ ¬ true ∈ bits → bits2uint(bits + bits0) = bits2uint(bits0)

Rule argument

name: bits2uint-zeros-02 rotate: F subst: [bits0, bits] → [bitsinvert(bits0) +1, bitsinvert(bits)]

Additional information

Used simplifier rules: ⊦ true ∈ bitsinvert(bits) ↔ false ∈ bits; Used terms: bitsinvert(bits0) +1, bitsinvert(bits)