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Proof step 3 from proof bits2int-range (previous step)

# bits = m + 1 ∧ # bits ≠ 0 ⊦ bits = [], ¬ 2 ^ n→i(m) + bits2int(bits) < 0 ∧ ¬ 2 ^ n→i(m) ≤ bits2int(bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
# bits = m + 1 ⊦ bits = [], ¬ 2 ^ n→i(m) + bits2int(bits) < 0 ∧ ¬ 2 ^ n→i(m) ≤ bits2int(bits)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ # bits = 0 ↔ bits = [];