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Proof step 1 from proof bits2int-rec-01 (conclusion)

⊦ boolvar ∧ bits.first ∧ bits ≠ [] → bits2int(bits + boolvar ') = ~(bits2uint(bitsinvert(bits.rest)) * 2 + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bits.first ⊦ bits = [], ~1 = bits2uint(bitsinvert(bits.rest)) * 2 + bits2int(bits + true ')

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0;% ⊦ ~ i = j ↔ i + j = 0;