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Proof step 4 from proof bits2int-rec-false (previous step)

¬(¬ (bits + false ').first ∧ bits + false ' ≠ []) ⊦ bits2int(bits + false ') = bits2int(bits) * 2, bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
bits.first ⊦ bits2int(bits + false ') = bits2int(bits) * 2, bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ' ≠ [];% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits ≠ [] → ((bits + bits0).first ↔ bits.first);