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Proof step 4 from proof bits2int-rec-true (previous step)

¬(true ∧ ¬ bits.first ∧ bits ≠ []) ⊦ bits2int(bits + true ') = bits2int(bits) * 2 + 1, bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
bits.first ⊦ bits2int(bits + true ') = bits2int(bits) * 2 + 1, bits = []

Rule argument

Additional information