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Proof step 8 from proof bits2int-sgn (previous step)

⊦ bits2int(sgn(boolvar ' + bits0)) = bits2int(mklist(boolvar, n) + sgn(boolvar ' + bits0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
bits ≠ [], ¬ (¬ bits.first) ∈ bits0 ⊦ bits2int(bits0 + bits) = bits2int(bits)

Rule argument

name: bits2int-sign rotate: F subst: [bits, bits0] → [sgn(boolvar ' + bits0), mklist(boolvar, n)]

Additional information

Used simplifier rules: ⊦ sgn(boolvar ' + bits) ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ sgn(boolvar ' + bits).first ↔ boolvar;% ⊦ boolvar ∈ mklist(boolvar0, n) → (boolvar ↔ boolvar0); (forward)% ⊦ ¬ false ∈ mklist(true, n); Used terms: sgn(boolvar ' + bits0), mklist(boolvar, n)