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Proof step 18 from proof bits2int-sign (previous step)

⊦ bits2int(bits0 + false ' + bits1) = bits2uint(bits1), bits0 = [], true ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits.rest)
Proof step 20:
¬(¬ (bits0 + false ' + bits1).first ∧ bits0 + false ' + bits1 ≠ []) ⊦ bits2int(bits0 + false ' + bits1) = bits2uint(bits1), bits0 = [], true ∈ bits0
Proof step 22:
¬ (bits0 + false ' + bits1).first ∧ bits0 + false ' + bits1 ≠ [] ⊦ bits2uint((bits0 + false ' + bits1).rest) = bits2uint(bits1), bits0 = [], true ∈ bits0

Rule argument

name: bits2int-pos-01 rotate: F subst: [bits] → [bits0 + false ' + bits1]

Additional information

Used terms: bits0 + false ' + bits1